(56^n+1) / (2^3n+2 * 7^n+1)
5-9 класс
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не совсем уверена, но возможно так:
(56^n+1)/(14^3n+2+n+1)=(56^n+1)/(14^4n+3)=4^-3n-3=1/(4^n+3)
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а)а+b=24
б)7х-y=56
в)12m-3n=48
г)7х-8y=56
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заранее спасибо )))
членом арифметической прогрессии an если a1=4 a4=85 4.вычислите сумму первых девятнадцати членов арифм.прогр. заданной формулой an=15 -3n
а) 3а+8b=24
б) 6с+5b=30
в) 12m-3n=48
г) 7x-8y=56
-12m^2n^ или
3n^2-5m^2-10m^2n^2??
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